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Consider the Relation

Algebra
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Consider the relation R = {(2x,x2) : x 2 Z} on Z. (1) Is 6R9? (2) Does 1 belong to the domain of the relation R? (3) Is the relation R a function from Z into Z? Explain.

Feb 12th, 2015

1) yes 6 R 9      

2) 1 is not a member of the domain

3) Yes because R is a subset of Z x Z

Feb 12th, 2015

can you show me any work to find your answers? 

Feb 12th, 2015

Do you mean an explanation of the answers


Feb 12th, 2015

yes

Feb 12th, 2015

1) Put x =3 (Which we can do since 3 is a member of Z) and we get (6,9) as a member of the Relation R

2) To get 1 as a member of R we must put in x = 1/2 the domain we have  and 1/2 is not  a member of Z


Feb 12th, 2015

1) Put x =3 (Which we can do since 3 is a member of Z) and we get (6,9) as a member of the Relation R

2) To get 1 as a member of R we must put in x = 1/2 

but  1/2 is not  a member of Z


Feb 12th, 2015

3) the relation is actually (0.0), (2,1), (4,4), (6,9) (8,16)....... and (-2,1), (-4, 4) (-6,9), (-8,16),,,,,

so this is a subset of ZXZ

Feb 12th, 2015

Sorry I did not read the Q properly 

Although it is a relation it is not a function because all the odd nimber have no partners

Feb 12th, 2015

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Feb 12th, 2015
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Feb 12th, 2015
Dec 8th, 2016
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