Physics: rock thrown upward

Physics
Tutor: None Selected Time limit: 1 Day

Feb 12th, 2015

use the equation of motion: 

y(t)=y0+v0t-1/2gt^2 

y(t)=height of projectile at any time, t 
y0=initial height = 34.6 m 
v0=initial speed (to be determined) 
t=time of flight 

we are told that the ball hits the ground (y=0) at t=4, so we have 

0=34.6+v0(4s)-1/2 (9.8m/s/s)(4s)^2 
0=34.6+4v0-78.4 
4v0=43.8 
v0=10.95m/s

Reference :- 

Feb 12th, 2015

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