P = 2L + 2W P = perimeter L = length W = width L = W + 4 P = 32 you get: P = 2L + 2W becomes: 32 = 2(W+4) + 2W which becomes: 32 = 2W + 8 + 2W which becomes: 32 = 4W + 8 subtract 8 from both sides of this equation to get: 32 - 8 = 4W combine like terms to get: 24 = 4W

divide both sides of this equation by 2 to get: W = 6 since L is equal to W + 4, this makes L = 10 you have: L = 10 W = 6 P = 2L + 2W = 20 + 12 = 32 this checks out ok. A = L*W A = 10*6 = 60 A equals area L = length W = width area of the rectangle is equal to 60 square cm. the question, however, was "what is the length?" the answer to that is that the length equals 10 cm.