The length of a rectangle is 4 cm longer than its width.

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 The length of a rectangle is 4 cm longer than its width. If the perimeter of the rectangle is 32 cm , find its area.
Feb 13th, 2015

P = 2L + 2W
P = perimeter
L = length
W = width
L = W + 4
P = 32
you get:
P = 2L + 2W becomes:
32 = 2(W+4) + 2W which becomes:
32 = 2W + 8 + 2W which becomes:
32 = 4W + 8
subtract 8 from both sides of this equation to get:
32 - 8 = 4W
combine like terms to get:
24 = 4W

divide both sides of this equation by 2 to get:
W = 6
since L is equal to W + 4, this makes L = 10
you have:
L = 10
W = 6
P = 2L + 2W = 20 + 12 = 32
this checks out ok.
A = L*W
A = 10*6 = 60
A equals area
L = length
W = width
area of the rectangle is equal to 60 square cm.
the question, however, was "what is the length?"
the answer to that is that the length equals 10 cm.

Feb 13th, 2015

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Feb 13th, 2015
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Feb 13th, 2015
Sep 19th, 2017
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