please help within five minutes

Chemistry
Tutor: None Selected Time limit: 1 Day

a. Calculate the pH of a 7.71×10-3 M solution of H2SO4

(Ka = 0.0120 for HSO4-)

b. Calculate [OH-] of a 5.45×10-1 M aqueous solution of pyridine (C5H5N, Kb = 1.7×10-9).

c. Calculate the pH of the above solution.

Feb 13th, 2015

Question a)

Please you have to solve this equation:

0.012 = y^2 / (0.00771 - y)

where y is the concentration of [H+], please keep in mind that since H2SO4 is a strong acid, then your chemical reaction is:

H2SO4 = H+   +   SO4-.

After a simple computation, I get:

y=[H+] = 0.0053= 5.3*10^(-3)

so we have_

pH = -Log(5.3*10^(-3))= 2.28

Feb 13th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
...
Feb 13th, 2015
...
Feb 13th, 2015
Dec 3rd, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer