please help within five minutes

label Chemistry
account_circle Unassigned
schedule 1 Day
account_balance_wallet $5

a. Calculate the pH of a 7.71×10-3 M solution of H2SO4

(Ka = 0.0120 for HSO4-)

b. Calculate [OH-] of a 5.45×10-1 M aqueous solution of pyridine (C5H5N, Kb = 1.7×10-9).

c. Calculate the pH of the above solution.

Feb 13th, 2015

Question a)

Please you have to solve this equation:

0.012 = y^2 / (0.00771 - y)

where y is the concentration of [H+], please keep in mind that since H2SO4 is a strong acid, then your chemical reaction is:

H2SO4 = H+   +   SO4-.

After a simple computation, I get:

y=[H+] = 0.0053= 5.3*10^(-3)

so we have_

pH = -Log(5.3*10^(-3))= 2.28

Feb 13th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Feb 13th, 2015
...
Feb 13th, 2015
Jun 25th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer