please help within five minutes

Chemistry
Tutor: None Selected Time limit: 1 Day

2NH3 NH4++NH2- K =1×10-33 at -50°C
ammonia is better proton acceptor than water the ionization of acid relatively enhance in liquid ammonia.ex acetic acid is strong acid in liquid ammonia

Estimate [NH4+](mol/L) in pure(ex neutral) liquid ammonia @-50°C

Feb 8th, 2015

2 NH3     =>     NH4+      +     NH2-     ;  K = 10^-33

  17                    0                     0

  -2x                  +x                   +x

(17 - 2x)            (x)                   (x)

K = (x^2)/(17-2x)    =>    (x^2) = (17-2x)K

                               =>    (x^2) = 17K -2Kx

                               =>    (x^2) + (2K)x - 17K = 0

using quadratic formula and substituting for K we get:    x ~ 1.3 * 10^-16 M = [NH4+]

Feb 14th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Feb 8th, 2015
...
Feb 8th, 2015
Dec 3rd, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer