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2NH3 NH4++NH2- K =1×10-33 at -50°C
ammonia is better proton acceptor than water the ionization of acid relatively enhance in liquid ammonia.ex acetic acid is strong acid in liquid ammonia

Estimate [NH4+](mol/L) in pure(ex neutral) liquid ammonia @-50°C

Feb 8th, 2015

2 NH3     =>     NH4+      +     NH2-     ;  K = 10^-33

  17                    0                     0

  -2x                  +x                   +x

(17 - 2x)            (x)                   (x)

K = (x^2)/(17-2x)    =>    (x^2) = (17-2x)K

                               =>    (x^2) = 17K -2Kx

                               =>    (x^2) + (2K)x - 17K = 0

using quadratic formula and substituting for K we get:    x ~ 1.3 * 10^-16 M = [NH4+]

Feb 14th, 2015

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