find the solution to the following equation x^2-10x=39 by transforming it into a perfect square trinominal

x^2 - 10 x = 39

Add (10/2)^2 to each side

x^2 - 10x + 25 = 39 + 25

(x-5)^2 = 64

Take the square root of each side

x - 5 = +/- 8

x - 5 = 8 x -5 = -8

x = 13 x = -3

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