If necessary, round to two decimal places. If the function value is not a real number and does not exist , state so. Evaluate F(x)= square root x-5 for F(41)

Please note that, we have:

F(41) = sqrt( 41 -5) = sqrt(36) = +/- 6,

namely therea re two distinct values of y, since F(41) = y, and precisely:

y_1 = 6

and

y_2 = -6

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