If necessary, round to two decimal places. If the function value is not a real number and does not exist , state so. Evaluate F(x)= square root x-5 for F(41)
Please note that, we have:
F(41) = sqrt( 41 -5) = sqrt(36) = +/- 6,
namely therea re two distinct values of y, since F(41) = y, and precisely:
y_1 = 6
y_2 = -6
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