1. subtract the second equation from the first to get

2y = -4

y = - 2 Now plug that back into any one of the given equations to get

-3x + 5(-2) = 2

-3x - 10 = 12

-3x = 12

x = - 4

2. Multiply the first equation by 4 and the second equation by 5 to get

28x + 20y = 60

-30x - 20 y = -70 Now add them to get

-2x = -10

x = 5 Now plug that into any of the given equations to get

7(5) + 5y = 15

35 + 5y = 15

5y = -20

y = - 4

3. If you get 6 = 6 that means there are an infinite number of solutions.

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