1. subtract the second equation from the first to get
2y = -4
y = - 2 Now plug that back into any one of the given equations to get
-3x + 5(-2) = 2
-3x - 10 = 12
-3x = 12
x = - 4
2. Multiply the first equation by 4 and the second equation by 5 to get
28x + 20y = 60
-30x - 20 y = -70 Now add them to get
-2x = -10
x = 5 Now plug that into any of the given equations to get
7(5) + 5y = 15
35 + 5y = 15
5y = -20
y = - 4
3. If you get 6 = 6 that means there are an infinite number of solutions.
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