Question #3

please youhave to apply this formula:

n = (P*V)/(R*T)

where P is the pressure, V is the volume of the gas, R is the gas constant, and Tis the temperature. Substituting your data, I get:

n = (0.68 * 0.75)/(0.08206 * 308.15) = 0.020 mol

since T = 273.15 + 35 = 308.15 °K

and P = 68900/101325 = 0.68 atm

Question #4

Here you have a thermodynamic transformation at constant pressure, so you have to apply this equation:

T2 = T1* V2/V1

substituting your data we get:

T2 = 296.15 * 38/35 = 321.53 °K

so T1 = 48.38 °Celsius

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