chemisty problem about molarity

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You need to make an aqueous solution of 0.189 M silver fluoride for an experiment in lab, using a 300 mL volumetric flask. How much solid silver fluoride should you add?

Oct 22nd, 2017

Silver Flouride = AgF2

MM of AgF2: 145.865 g/mol

Molarity = mols/liters

So now plug and chug:  

0.189 M = mols/0.3 L (same as 300ml)

Solve for mols and you get 0.0567 mols.  Now you need to multiply this by the MM to get the grams of silver fluoride necessary.  

.0567 mol x 145.865 g/mol = 8.27 grams of silver fluoride

Feb 16th, 2015

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Oct 22nd, 2017
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Oct 22nd, 2017
Oct 23rd, 2017
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