You need to make an aqueous solution of 0.189 M silver fluoride for an experiment in lab, using a 300 mL volumetric flask. How much solid silver fluoride should you add?
Silver Flouride = AgF2
MM of AgF2: 145.865 g/mol
Molarity = mols/liters
So now plug and chug:
0.189 M = mols/0.3 L (same as 300ml)
Solve for mols and you get 0.0567 mols. Now you need to multiply this by the MM to get the grams of silver fluoride necessary.
.0567 mol x 145.865 g/mol = 8.27 grams of silver fluoride
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