How many grams of Ag2CO3 will precipitate when excess (NH4)2CO3 solution is added to 66.0 mL of 0.775 M AgNO3 solution?
0.066 L * 0775 mol AgNO3/L * 1 mol Ag2CO3 / 2 mol AgNO3 * 275.74 g Ag2CO3/ 1 mol
= 7.05 g Ag2CO3 precipitate
Please best answer
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?