solution stoichiometry

Chemistry
Tutor: None Selected Time limit: 1 Day

How many mL of 0.581 M HI are needed to dissolve 9.58 g of MgCO3?

2HI(aq) + MgCO3(s) MgI2(aq) + H2O(l) + CO2(g)
Feb 17th, 2015

Molarity= mol/L

(.581 M) x 2 = (9.58g/84.31g/mol)/L

L= .0978  or  97.8 ml

Feb 17th, 2015

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Feb 17th, 2015
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Feb 17th, 2015
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