What volume of a 0.204 M hydrobromic acid solution is required to neutralize 11.9 mL of a 0.167 M potassium hydroxide solution? _____ mL hydrobromic acid
(0.204)V = (0.0119)(0.167)
=> V = (0.0119)(0.167)/(0.204) = 0.00974 = 9.74 mL
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