Then, 74 % (volume of atoms only) would be: 74 x 60.42 A^{3 }/ 100 = 44.71 A^{3}

V = 4/3 πr^{3 }

Thus, r = (V/ (4/3 π))^{1/3 }= (3x44.71/4 π)^{1/3} = 2.202 A

Density = m/V = 780.47 amu /60.42 A^{3}

1 amu = 1.66054 x 10^{-24 }g

Thus, 760 amu = 12.96 x 10^{-22} g, since in order to convert to grams: 760 amu x 1.66054 x 10^{-24 }g / 1 amu = 12.96 x 10^{-22} g

1 A^{3} = (10^{-8 })^{3 }cm^{3 }

Thus, 60.42 A^{3 }in cm^{3 }is = 60.42 A^{3 }x (10^{-8 })^{3 }cm^{3 }/ 1 A^{3 }= 60.42x10^{-24} cm^{3 }

Density = m/V = 12.96 x 10^{-22} g/60.42 A^{3 }= 12.96 x 10^{-22} g / 60.42x10^{-24} cm^{3 }= 21.45 g/ cm^{3}

can you check 2 and 3

what do you mean by 2 and 3?

the ones you labeled 2 and 3, i got different answers. you had 2.202 and 21.45

r^{3} = V / 1.33 π = (44.71 A^{3}) / (1.33)(3.14) = 10.71A^{3}

r = 3root of 10.71A^{3} = 2.2 A

just tried other ways.... still comes out 2.2 A

You can check it by your calculator, it's easy.

and if 2 is right, then 3 is correct accordingly

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