Find the pH of a solution.

Chemistry
Tutor: None Selected Time limit: 1 Day

What is the pH of a solution obtained by mixing 30.00 mL of 0.500 M HCl and 30.00 mL of 0.250 M NaOH?

Feb 17th, 2015

#mol HCl = 0.50M * 0.03L = 0.015 mol HCl

#mol NaOH = 0.25M * 0.03L = 0.0075mol NaOH

HCl clearly has the more moles.

Thus, the excess number of moles of HCl is

0.015-0.0075 = 0.0075 mol

#M HCl = 0.0075mol/0.06L = 0.125M HCl

(Since 0.06L used since total volume of both solutions is 30mL )

We then know that

pH = -log[H3O+] = -log[HCl]

Therefore,

pH = -log(0.125)= 2.079441542=2.08

quite acidic which is obvious because of greater mass of HCL

Reference:

https://answers.yahoo.com/question/index?qid=20080504193856AADPB6x


Feb 17th, 2015

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Feb 17th, 2015
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Feb 17th, 2015
Dec 4th, 2016
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