molar mass of unknown acid


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if 39.85mL of 0.09827 M NaOH is required to neutralize 0.7997 g of an unknown acid, HA, what is the molar mass of the unknown acid?

Feb 17th, 2015

molar mass for NaOH is 40g/mol

given 0.09827moles in 1000ml

we try to find how many moles are in 39.85ml

moles= (39.85*0.09827)/1000= 0.00392 moles

assuming a reaction ratio of 1:1

moles of the unknown acid neutralised= 0.00392 moles

molar mass= mass/moles= 0.7997/0.00392=204

the molar mass of the unknown acid is 204 g/mol

please best this answer

Feb 17th, 2015

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Feb 17th, 2015
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Feb 17th, 2015
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