if 39.85mL of 0.09827 M NaOH is required to neutralize 0.7997 g of an unknown acid, HA, what is the molar mass of the unknown acid?
molar mass for NaOH is 40g/mol
given 0.09827moles in 1000ml
we try to find how many moles are in 39.85ml
moles= (39.85*0.09827)/1000= 0.00392 moles
assuming a reaction ratio of 1:1
moles of the unknown acid neutralised= 0.00392 moles
molar mass= mass/moles= 0.7997/0.00392=204
the molar mass of the unknown acid is 204 g/mol
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