Question Description
I’m stuck on a Algebra question and need an explanation.
1. Choose 2 integers. Then write an equation with those roots in standard form. how would the equation change if the signs of the 2 roots were switched. 2. Explain why you can't solve x(x+5) = 24 by solving x = 24 and x + 5 = 24

Final Answer

1.
Let the integers be 3 and -6
x2+3x-18=0
If the signs are switched
The numbers are -3 and 6
x2-3x-18=0
2.x(x+5) =24
Right hand side is not zero but 24
So we cannot write x=24 or x+5 =24
X2+5x-24=0
X2+8x-3x-24=0
X(x+8)-39X=8)=0
(x+8)(x-3)=0
Since RHS = 0, we can write
X= -8 or x =3
