The next 11 questions are related to the titration of 25.00 mL of a 0.0800 M acetic acid solution with 0.0700 M KOH. Assume that the temperature is 25 ^{o}C.

What volume of KOH has been added at the half-equivalence point?

Please note that before I have made an error. In order to find the value of the volume v of the KOH added at half-equivalence point, you have to solve this equation:

(200-7v) / (25 + v) = 3.162 * 10^(-2)

and solving that equation for v I get:

v = 28.327 mL

Feb 18th, 2015

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