Using tabulated Ka and Kb values, calculate the pH of the following solutions.
1. A solution containing 2.5×10-1 M HCOOH and 3.0×10-1 M HCOONa.
2. 650.0 mL of solution containing 16.0 g of HNO2 and 50.0 g of NaNO2.
1. HCOOH <===> COOH- + H+
I. 2.5e-1 3e-1 0
C. -x +x +x
E. 2.5e-1 -x 3e-1 +x x
Ka = (3e-1 +x)*x / (2.5e-1 -x) = 1.8e-4
x = 1.125e-5
pH = - log(1.125e-5) = 4.95
2. Work exactly the same way after calculating the molarity of the initial concentrations.
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