Time remaining:
please help within five minutes

Chemistry
Tutor: None Selected Time limit: 0 Hours

 questions are related to the titration of 25.00 mL of a 0.0800 M acetic acid solution with 0.0700 M KOH. Assume that the temperature is 25 oC. 

What volume of KOH has been added at the half-equivalence point? 

Feb 19th, 2015

We apply the formular ;

C1 V1 = C2 V

then we substute  is given,

 0.0800 x 25  =  0.0700 x V2

V2 =   0.0800 x 25/  0.0700

  =28.571  

Vol of KOH=28.571ml


Feb 19th, 2015

Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.
Click to visit
The Notebank
...
Feb 19th, 2015
...
Feb 19th, 2015
Mar 29th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer