Description
Calculate the mass of Pb3(PO4)2 (Ksp = 1.00×10-54) which will dissolve in 100 ml of water.
Explanation & Answer
As the reaction progresses, due to the stoichiometry of the reaction, +3s of [Pb2^+] and +2s of [PO4^3-] will be made.
Ksp = 1.00x10^-54 = [Pb^2+]^3 [PO4^3-]^2 = [3s]^3 [2s]^2 = 108s^5
s = 6.21x10^-12 M
b) (6.21x10^-12 mol Pb3(PO4)2 / 1 L) x (811.54 g Pb3(PO4)2/ 1 mol Pb3(PO4)2) = 5.04x10^-9 g Pb3(PO4)2 / 1 L
c) Same process as parts a) and b), but with a different reaction.
PbCrO4 <--> Pb^(2+) + CrO4^(2-)
Plumbous ion concentration is increased by s, chromate ion concentration is increased by s.
2.00x10^-16 = s^2
s = 1.41x10^-8 mol/ L
Convert moles to grams to find solubility in terms of grams, then convert liters to mL in order to find the mass of PbCrO4 that will dissolve in 100 mL.
(1.41x10^-8 mol/ L) x (323.2 g / mol) x (1 L / 1000 mL) x (100 mL) = 4.56x10^-7 g PbCrO4
Review
Review
24/7 Homework Help
Stuck on a homework question? Our verified tutors can answer all questions, from basic math to advanced rocket science!
Similar Content
Related Tags
The Kite Runner
by Khaled Hosseini
The Iliad
by Homer
Fools Crow
by James Welch
The Underground Railroad
by Colson Whitehead
Silas Marner
by George Eliot
Alice in Wonderland
by Lewis Carroll
Little Women
by Louisa May Alcott
The Point of it All - A Lifetime of Great Loves and Endeavors
by Charles Krauthammer