Determine the magnitude of the electric field at point 2 in the figure.

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Feb 20th, 2015

The dotted lines represent equipotential lines.  So any point along each line will equal the voltage associated with it.  In this case, point two is equal to point 1.  They are both 50 V.

Feb 20th, 2015

I have point 1 equivalent to 3,800 V/m (based off a total guess). I put the same answer in for point 2, however it says that it is wrong. I feel like I am getting the distance wrong. I understand where the points lay in the equipotential lines and their voltage. Using the equation E = V/r 

Feb 20th, 2015

Try 5,000 V/m

I arrived at this answer by taking 1 cm (the distance point 2 is away from the 0 V equipotential line) and using it in the equation E=V/r.

E=50V/.01m=5000 V/m

Feb 20th, 2015

I too have also tried that answer. Unfortunately that did not work either. 

Feb 20th, 2015

If point 1 is equivalent to 3,800 V/m the try twice that for point two, or 7,600 V/m.

Feb 20th, 2015

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