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Chemistry
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A solution made by mixing 100.00 mL of 1.000 M HOCl with 65.00 mL of 0.900 M NaOH.

For HOCl, Ka = 3.5×10-8.
Feb 21st, 2015

Please note that, we have the subsequent concentrations:

[HClO] (Before of the neutralization) = 100 mMol

[NaOH] = 0.9*65 = 58.5 mMol

{HClO] (After the neutrlization) = 100-58.5 = 41.5

Total volume = 100+65 = 165 mL

So we get:

[H+] = 41.5 / 165 = 0.2515

and:

PH = 0.6


Feb 21st, 2015

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