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Chemistry
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ionic solid SrF2. When dissolved in pure water, its solubility is found to be 8.9×10-4 M.

Give the formula of the anion in this compound.

What is the concentration of this anion in a saturated solution of SrF2?

Determine the value of Ksp for SrF2.

Feb 22nd, 2015

a) Formula of ion = F^-

b) concentration of anion

The solubility is 8.9×10^-4 M.  For each mol of SrF2 that goes into solution, there will be two mols of F-.

 = 8.9×10^-4 M  * 2

= 1.8×10^-3 M

c) Ksp for SrF2 

ksp = [Sr^2+] * [F-] ^ 2  

       = (8.9×10^-4 M) * (1.8×10^-3 M) ^2

       = 2.8 ×10^-9

agrees in magnitude with literature value


Feb 22nd, 2015

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