Body temperatures of healthy adults are normally distributed with a mean of 96.20 degrees F and a standard deviation of 0.82 degrees F, what is the percentile score if your temperature is 97 degrees F
Standard z-score = (97 -96.2)/0.82= 0.9756
We now want area to the left
P( z=<0.9756) = 0.8354 = 83.54 percentile score
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?