Body temperatures of healthy adults are normally distributed with a mean of 96.20 degrees F and a standard deviation of 0.82 degrees F, what is the percentile score if your temperature is 97 degrees F

z=(x-u)/σ

where z is the z score

u population mean

x sample mean

z=(97-96.2)/0.82

the score is=0.9756

or 97.56%

Best my answer please

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