Science
You throw a 4kg rock directly down at 6m/s from the top of a 18m cliff. Calculat
Question Description
I don’t know how to handle this Physics question and need guidance.
a)initial KE
b)Initial PE
c) V when rock is 13m above ground
d) V rock will hit the ground
e)distance the rock is driven into the mud if the mud exerts a steady upwards force of 4000N
f)speed the rock hits ground if initially thrown up at 6m/s
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Final Answer
a) Potential energy is mgh where h = vertical distance.
b) Kinetic energy is (1/2)mv^2
c) It has gained energy mgh where h is the vertical distance it fell (so far). Add that to the initial KE.
d) It has gained energy mgh where h is the total vertical distance it fell. Add that to the initial KE.
e) Work F * d = kinetic energy, because the force has to remove that kinetic energy from the rock.
f) Exactly the same
madhavant
(2757)
UC Berkeley
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