### Question Description

I don’t know how to handle this Physics question and need guidance.

a)initial KE

b)Initial PE

c) V when rock is 13m above ground

d) V rock will hit the ground

e)distance the rock is driven into the mud if the mud exerts a steady upwards force of 4000N

f)speed the rock hits ground if initially thrown up at 6m/s

## Final Answer

a) Potential energy is mgh where h = vertical distance.

b) Kinetic energy is (1/2)mv^2

c) It has gained energy mgh where h is the vertical distance it fell (so far). Add that to the initial KE.

d) It has gained energy mgh where h is the total vertical distance it fell. Add that to the initial KE.

e) Work F * d = kinetic energy, because the force has to remove that kinetic energy from the rock.

f) Exactly the same