please we can compute the volume occupied by the methanol, as follows:
V = (71.5/32 * 0.08206 * 300.15) /( 140/760) = 323.82 liters
since T = 27+273.15 = 300.15 °K, and P = 140/760 = 0.184 atm
so the pressure exerted by the clucose is:
P = (17/180 * 0.08206*300.15) / 323.82 *760 = 5.46 mm of Hg
and the total pressure by the Dalton's Law, is:
140+5.46 = 145.46 mm of Hg
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