chemistry question general chem


label Chemistry
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For the reaction, calculate how many grams of the product form when 18.4g of Ca completely reacts. Assume that there is more than enough of the other reactant. Ca(s)+Cl2(g)→CaCl2(s)

Feb 24th, 2015

The mol of Ca are:

18.4/40= 0.46

then we get 0.46 mol of CaCl2, since the molecular mass of CaCl2 is 111, then we get:

0.46*111 = 51.06 grams of CaCl2

Feb 24th, 2015

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