##### physical science 9th

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How long (time) would you travel up (Velocity final = 0) if you jump up on a trampoline (Acceleration of gravity on earth is - 9.8 m/s^2), if your initial velocity was 6 m/s?

Feb 24th, 2015

here we have to solve this equation:

0 = 6 -9.8 * t

so:

t = 6/9.8 = 0.612 seconds

Feb 24th, 2015

What do you mean?

Feb 24th, 2015

I meant that time needed to reach null speed starting with a speed of  6m/s is 0.612 seconds

Feb 24th, 2015

How high (Distance) would you travel up in the above problem if your initial velocity was 6 m/s and the acceleration on the earth is -9.8 m/s^2? Use your answer from Question 1 for your Time.

Feb 24th, 2015

Can you help me with that one to?

Feb 24th, 2015

in order to get the requested distance, you have to compute this:

d = 6 * 0.612 - 0.5 * 9.8 * (0.612)^2 = 3.672 - 1.835 = 1.837 meters

Feb 24th, 2015

You throw a ball to a friend that is 25 meters away (Distance). How fast was the ball traveling forward (velocity initial) when it left your hand if it takes 4 seconds (Time) to reach your friend? (Acceleration = 0)

Feb 24th, 2015

Feb 24th, 2015

I didnt see it

Feb 24th, 2015

speed = 25/4 = 6.25 seconds

Feb 24th, 2015

You throw a ball to a friend. How high did it go (Distance) if it takes 4 seconds to reach him (YOUR TIME = 2 SECOND), acceleration from gravity on earth is always -9.8 m/s^2, and your velocity initial is your answer from Question 4. question 4's answer was 6.25

Feb 24th, 2015

oops.. preceding answer is speed = 6.25 m/sec

Feb 24th, 2015

after 2 seconds we have: the initial speed is

v_0 = 9.8* 2 = 19.6 m/sec

so the requested distance is:

d = 19.6 * 2 - 9.8 * 2= 19.6 meters

Feb 24th, 2015

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Feb 24th, 2015
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Feb 24th, 2015
Sep 22nd, 2017
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