physical science 9th

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ovoorz

Science

Description

How high (Distance) would you travel up in the above problem if your initial velocity was 6 m/s and the acceleration on the earth is -9.8 m/s^2? Use your answer from Question 1 for your Time.

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Explanation & Answer

dY = vi*t + 1/2at^2

dY = 6m/s*0.612s + 1/2(-9.8m/s^2)(0.612s^2)

dY = 3.672m + (-1.83m) = 1.842m


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