physical science 9th

Science
Tutor: None Selected Time limit: 1 Day

Feb 24th, 2015

dY = vi*t + 1/2at^2

dY = 6m/s*0.612s + 1/2(-9.8m/s^2)(0.612s^2)

dY = 3.672m + (-1.83m) = 1.842m

Feb 24th, 2015

So my answer is 1.842?

Feb 24th, 2015

Yes, it should be 1.842 meters

I took the 0.612 seconds from the time that I calculated in your previous question

Here vi is your initial velocity.  t is the time that was claculated before.  and a is acceleration

Does that make sense?

Feb 24th, 2015

Yes 

Feb 24th, 2015

OK.  :)

Feb 24th, 2015

I wanted to inform you, if you don't already know, that Bilal is using the wrong equations in his answers.  For example on the throwing the ball question, it is impossible that a ball could travel 25 meters and not have any initial velocity.

Feb 24th, 2015

That I was just using yours and the Micheals guys answers 

Feb 24th, 2015

Okay, good!  Just wanted to make sure you weren't using the wrong thing.  :)

Feb 24th, 2015

Thank you 

Feb 24th, 2015

Why did the ball experience no acelleration?

Feb 24th, 2015

You're welcome! :)

Feb 24th, 2015

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