pressure calculation

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A mixture of helium and hydrogen gases is maintained in a 5.70 L flask at a pressure of 3.92 atm and a temperature of 22 °C. If the gas mixture contains 1.70 grams of helium, the number of grams of hydrogen in the mixture is ____ g.

Feb 24th, 2015

ntotal = PV / RT = 3.92 * 5.7 / 0.0821*(22+273)

ntotal = 0.923 mol

1.70 g He * 1 mol He/ 4 g He = 0.425 mol He

nH2 = 0.923 - 0.425 = 0.498 mol H2

0.498 mol H2 *2 g / mol = 0.996 g H2 

Feb 24th, 2015

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Feb 24th, 2015
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Feb 24th, 2015
Jun 23rd, 2017
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