A mixture of helium and hydrogen gases is maintained in a 5.70 L flask at a pressure of 3.92 atm and a temperature of 22 °C. If the gas mixture contains 1.70 grams of helium, the number of grams of hydrogen in the mixture is ____ g.
ntotal = PV / RT = 3.92 * 5.7 / 0.0821*(22+273)
ntotal = 0.923 mol
1.70 g He * 1 mol He/ 4 g He = 0.425 mol He
nH2 = 0.923 - 0.425 = 0.498 mol H2
0.498 mol H2 *2 g / mol = 0.996 g H2
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