A 1.36 gram sample of an unknown gas is found to occupy a volume of 0.979 L at a pressure of 642 mm Hg and a temperature of 48 °C. The molecular weight of the unknown gas is _____ g/mol.Assume ideal behavior.

from PV= nRT

n = PV/RT = [(642/760)*0.979]/(0.08206*321)= 0.0314

so molecular mass = 1.36/0.0314 = 43.32

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