Dissociation Constant of a Weak Acid

Chemistry
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What is the pH of a solution obtained by mixing 30.00 ml of 0.500 M HCl and 30.00 mL of 0.250 M NaOH?

Feb 25th, 2015

convert to mols for both the HCl and NaOH

mols HCl = 0.03000L * 0.500 M = 0.0150 mols

mols NaOH = 0.03000L * 0.250 M = 0.00750 mols

Neutralization occurs, whereby all of the NaOH is used up.

Calculating the mols of HCl remaining...

0.0150 - 0.00750 = 0.00750 mols HCl

All of the HCl dissociates, meaning we have 0.00750 mols of H+

The pH is given by taking the -log of [H+]

-log(0.00750) 

= 2.125 (with sigfigs in mind 

Feb 25th, 2015

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