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if a and b are integers divisible by 4, the a^2+bc+a is a multiple of 4 for any integer c

Oct 17th, 2017

a=4m where m is an integer

b= 4n where n is an integer

a2+bc+a= a(a+1)+bc= 4m(4m+1)+4nc= 4[m(m+1)+nc]

Since c is an integer and m and n are integers,m(m+1)+nc is an integer . so for any c

a2+bc+a is a multiple of 4 or divisible by 4

Feb 25th, 2015

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