Find the angle between the given vectors to the nearest tenth of a degree.u = <-5, -4>, v = <-4, -3> -9.1° 1.8° 0.9° 11.8°

(-5,-4) (-4,-3)

tan theta1 = 4/5

tan theta2 =3/4

tan theta = (4/5-3/4)/(1+4/5*3/4)= (16/20-15/20) /(1+3/5)=1/20*5/8=1/32

tan ^{-1 }(1/32) =1.789^{0 }=1.8^{0}

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