For the 20 kg body, projection on the vertical downward axis, Physics Exercise help

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nygnjvy89

Science

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I need step by step answer for only Ex. 3 .. I have started the answer but I don't think I'm going right..

I've attached the introduction and Ex. 1 just to review the solution if needed..

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the same tenssien both side has 5 T T 7 10 g zog 1 For 10 g: T-109 10 a V for 20 g: 20g-T = 20a I (10 a +10g) 20g - (100+10g) = 200 20g - 10a - 10g = 209 10g 10x9,8 9 二3.27m/52 - 300 a 9 - 109 こ 30 30 Then, T= 10a + 10g 10 X 3.27 + 10x 9.8 Ex:2) T-o = 10 a to v 20g-T = 200. - 0 10kg 10 kg smooth 20 kg T= 10 a 20 g - 10 a = 20a normat force n -2- T Compl ete it 109 Definition of normal al to the surface - 3- AT 209 Ex, 5 For 20 kg: 20g -T= 209 (1) 10% Smooth 2 20kg (2) 30 7 for 10 kg step Eink ayn angle complete (1) it T = (20g + 20 a { {a=4.98 log sin 30 loge COS 30° LTEM 20g 20g+200-10g Sin 30 = 10a 20g 4 20a - 59 = 10a 15g = -10a 15x9.8 1089.8 4.9 -)0 4,9 Newton's laws of motion: 1 - If there is no external force, object remains stafimary or moves with constant speed. 3- Every action has equal and opposite reaction. m a 2- mas Net force action Kg acceleration m/s² on an object 52 2 w in 30N 50N 2ON 30 50 (Fth 300 nr. Unit of force is N = Newton (Kg. m - 1 N Weight (W) = mass X gravikiond accelerational) m xg - Ex. Note: 1).220 - Fnet - 50N-304 - 200 80N 2 a =) Fuet - 50N+30N=80N Tenssion (T) Fret 3) Le . Fuet = √50 ²+ 30² mg Feet = √ F x² + F² O= tant # / Ex:1) 1-Draw "free-body diagrams" for each mass. Lur 2- Write Fuer= ma for each meass sepamdely in the direction of the motion. 3- Do your algebra. 1 1 50M (FX) جنوری تعمیر (F Fx *** verless Pulley On ZOK
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Explanation & Answer

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For the 20 kg body, projection on the vertical downward axis:
20𝑔 − 𝑇 = 20𝑎....


Anonymous
Excellent resource! Really helped me get the gist of things.

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