Chemistry Titration equation

Chemistry
Tutor: None Selected Time limit: 1 Day

Calculate the OH− concentration after 52.6

mL of the 0.100 M KOH has been added to

25.0 mL of 0.200 M HBr. Assume additive

volumes.

Answer in units of M.

NO SIG FIGS, NEED FULL ANSWER

Feb 27th, 2015

KOH + HBr =====> H2O + KBr

52.6 ml * 1 L / 1000 mL * 0.100 mol/L = 0.00526 mol KOH

25.0 ml * 1 L / 1000 mL * 0.200 mol/L = 0.005 mol HBr

KOH is in excess

After reaction occurs there are 0.00026 mol KOH in 77.6 mL of solution

[OH-] = 0.00026 / 77.6 mL * 1000 mL / 1 L = 0.00335 M

pOH = - log(0.00335) = 2.475

pH = 14 - 2.475 = 11.5251116267

Please best answer.

Feb 27th, 2015

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