Calculate the concentration of Zn2+ in saturated
solution of zinc sulfide (ZnS) given that
Ksp of zinc sulfide is 2.54 × 10−24
Answer in units of mol/L.
No sig figs, need full, unedited answer
ZnS ====> Zn2+ + S2-
Ksp = [Zn2+] [S2-] = 2.54e-24
Let x = the ion concentration
x^2 = 2.54e-24
x = 1.594e-12 M
Please best answer.
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