A solution in equilibrium with solid barium
phospate is found to have a barium
ion concentration of 0.0005 M and a Ksp of
4.1 × 10−23. Calculate the concentration of
Answer in units of mol/L.
Ba3(PO4)2 ======> 3 Ba2+ + 2 PO43-
Initial 0 0
Change +3x +2x
Equilibrium 3x 2x
0.0005M = 3 x
x = 0.0001667M
[PO4 3-] = 2*0.0001667 = 0.000333 M
Please best answer.
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