A solution in equilibrium with solid barium
phospate is found to have a barium
ion concentration of 0.0005 M and a Ksp of
4.1 × 10−23. Calculate the concentration of
Answer in units of mol/L.
Ba3(PO4)2 ----- 3 Ba+2 + 2 PO4^-3 since a Ksp is equal to the concentrations of the products raised to the power of their coefficients then Ksp = [Ba+2]^3 [PO4]^2 (5 X 10^-4 )^3( PO4)^2 = 4.1 X 10^-23 (PO4)^2 = 4.1 X 10^-23 / 125 X 10 ^-12 PO4 ^-3 = 3.20 X 10^-13 M (or mol/l)
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