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Find area under a curve for [-(x-18)^2/2]+24 between x=12 and x=24

Mathematics
Tutor: None Selected Time limit: 0 Hours

Mar 1st, 2015

Find area under a curve for

[-(x-18)2/2]+24 between x=12 and x=24

-(x-18)3/6+24x between 12 and 24

The first part is zero because of symmetry w.r.t 18

24x between 12 and 24

24*12 =288



Mar 1st, 2015

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