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Statistics questions

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mean of 503 standard deviation of 111 a university plans to send letters to students whoses scores are in top 8% what is the minimum score required for a letter of recognition 

Mar 2nd, 2015

Top 8 percentile value = 1.405

Score = 503+111* 1.405 = 658.955 = 659

Mar 2nd, 2015

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Mar 2nd, 2015
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Mar 2nd, 2015
Jun 28th, 2017
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