find the value of z such that 0.7698 of the area lies between -z and z round to 2 decimal places
0.7698/2 = 0.3849
0.5-0.3849 = 0.1151
P ( z < -1.2 ) = 0.1151
P (-1.2 < z <1.2) = 0.7698
Z value = 1.20
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