tan 15° = tan(π/12)

= tan(π/3 − π/4)

= [tan(π/3) − tan(π/4)] / [1 + tan(π/3) tan(π/4)]

= [(√3)− 1] / [1 + (√3)×1]

= [(√3)− 1] / [(√3) + 1]

= [(√3)− 1]² / [(√3) + 1]×[(√3) − 1]

= [3 − 2(√3) + 1] / [3 − 1]

= [4 − 2(√3)] / 2

= 2 − √3

Secure Information

Content will be erased after question is completed.

Enter the email address associated with your account, and we will email you a link to reset your password.

Forgot your password?

Sign Up