The sum of two numbers is 3 more than four times the first number. Their difference is 10 less than twice the second number. Find each of the numbers.

x+y= 3x

x-y= y-10

y=2x+0

-2y= -x-10

solving by elimination

-2(y=2x+0

-2y= -2x+0

- ( -2y= -x-10

0= -x+10

x=10

y=2x

y=2(10)

y=20

the two numbers are 10 and 20

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