Factor out the Great common factor

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38x^2y - 19x^2y^4

just to verify I think the result will be    -19x^2y ( 2x^2y^4) if not can some body help me

Mar 3rd, 2015

38x^2y - 19x^2y^4

Taking x^2y common, then

x^2y(38 - 19y^3)

Now we take 19 common, then

19x^2y(2 - y^3)

Hence  38x^2y - 19x^2y^4 = 19x^2y(2 - y^3)

Mar 3rd, 2015

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Mar 3rd, 2015
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Mar 3rd, 2015
Jun 27th, 2017
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