The population proportion was estimated to be 0.22. How large a sample would be required in order to estimate readers at or below eighth grade reading levels at 80% confidence level with an error of at most 0.03 round answer to next integer
I hope this page helps...the formula I would use would be the one in the box where we're solving for n, the sample size.
p is the pop proportion = 0.22
E is the error = 0.03
Za/2 is the critical value associated for 80% confidence and was calculated to be z = 1.282
Essentially, we want the z-score that leaves an area of (1 - 0.8) / 2 = 0.1 to the right--equivalent to a z-score of 0.900.
Calculated, the sample size comes out to be 313.20 rounded up to 314
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?