find the value of z such that 0.8904 of the area lies between -z and z
1 - 0.8904 = 0.1096, where 0.1096 is the area not between z- and z
Dividing this outside area by 2 yields an area of 0.0548
Looking up a = 0.0548 in the z-table we find that z = -1.60
so z is 1.60
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