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Calculate the molarity of the solution that contains 14.0 g of Fe2O3 in 414 mL of solution. 

2,,A solution is made by dissolving 5.52 g of SnSO4 into enough water to make 440 mL of solution. What is the molarity of the solution? 

Mar 3rd, 2015

molarity=moles of solute/volume of solution in liters

First you have to calculate the number of moles in SnSO4. The molar mass of SnSO4 is 214.77g/mol. Then you do a conversion factor and multiple 5.52g by the molar mass. So. 5.52g x 1mol/214.77g. You need grams on the bottom so the units will cancel out at you'll be left with moles. The total number of moles is .0257. Now cover mL to L by dividing by 1000. So 440mLx 1L/1000mL=.440L All you have to do now is divide moles by volume. molarity=.0257moles/.440L=.058M. 

Mar 3rd, 2015

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Mar 3rd, 2015
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Mar 3rd, 2015
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